During an illumination mission, if the flare burns out 60 mils above the ground and the OT factor is 2, what correction should the Observer send for HOB?

Study for the 2nd Battalion, 15th Field Artillery Regiment MQF Test. Use quizzes and flashcards for better understanding, each question comes with hints and explanations to aid your exam preparation!

For an illumination mission, determining the appropriate correction for Height of Burst (HOB) involves understanding the relationship between the flare's burn-out altitude, the OT factor (which represents the adjustment needed based on the distance to the target), and the way these elements interact in the field.

In this scenario, the flare burns out at 60 mils above the ground. To convert the height from mils to meters, we can use a rule of thumb that every 1000 mils equals 1 meter at 1000 meters away. Therefore, 60 mils equates to a height of 0.06 meters, or approximately 6 centimeters above the ground.

Next, applying the OT factor of 2 means that the distance needs to be adjusted accordingly. The OT factor effectively doubles the required correction. So, if 60 mils converts to a height of 60 meters (assuming the target is a significant distance away), the observer would need to send a correction of 2 times the initial height related to the OT factor.

Calculating the total adjustment gives us:

  • Original height = 60 meters

  • OT factor = 2

  • Required correction = 60 * 2 = 120

This correction means that the

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